mirror of
https://github.com/1f349/violet.git
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86 lines
2.0 KiB
Go
86 lines
2.0 KiB
Go
package utils
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import (
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"strconv"
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"strings"
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)
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// SplitDomainPort takes an input host and default port then outputs the domain,
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// port and true or empty values and false if the split failed
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func SplitDomainPort(host string, defaultPort int) (domain string, port int, ok bool) {
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a := strings.SplitN(host, ":", 2)
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switch len(a) {
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case 2:
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domain = a[0]
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p, err := strconv.Atoi(a[1])
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port = p
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ok = err == nil
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case 1:
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domain = a[0]
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port = defaultPort
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ok = true
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}
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return
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}
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// GetDomainWithoutPort takes an input domain + port and outputs the domain
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// without the port.
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//
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// example.com:443 => example.com
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func GetDomainWithoutPort(domain string) string {
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// if a valid index isn't found then return false
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n := strings.LastIndexByte(domain, ':')
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if n == -1 {
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return domain
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}
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return domain[:n]
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}
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// ReplaceSubdomainWithWildcard returns the domain with the subdomain replaced
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// with a wildcard '*' character.
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//
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// www.example.com => *.example.com
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func ReplaceSubdomainWithWildcard(domain string) (string, bool) {
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// if a valid index isn't found then return false
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n := strings.IndexByte(domain, '.')
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if n == -1 {
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return "", false
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}
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return "*" + domain[n:], true
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}
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// GetParentDomain returns the parent domain stripping off the subdomain.
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//
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// www.example.com => example.com
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func GetParentDomain(domain string) (string, bool) {
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// if a valid index isn't found then return false
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n := strings.IndexByte(domain, '.')
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if n == -1 {
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return "", false
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}
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return domain[n+1:], true
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}
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// GetTopFqdn returns the top domain stripping off multiple layers of subdomains.
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//
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// hello.world.example.com => example.com
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func GetTopFqdn(domain string) (string, bool) {
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var countDot int
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n := strings.LastIndexFunc(domain, func(r rune) bool {
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// return true if this is the second '.'
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// otherwise counts one and continues
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if r == '.' {
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if countDot == 1 {
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return true
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}
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countDot++
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}
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return false
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})
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// if a valid index isn't found then return false
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if n == -1 {
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return "", false
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}
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return domain[n+1:], true
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}
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